Cute math problem for the next club ride:
How many cyclists must be on the club ride before the odds of two riders having the same birthday hits 50% -Mike G
Cute math problem for the next club ride:
How many cyclists must be on the club ride before the odds of two riders having the same birthday hits 50% -Mike G
People literally don't believe me when I tell them the answer to this, sometimes even after explaining the math.
Even more odd, it's practically 100% (99.999%) probability of a shared birthday for a group of 100.
Veridical paradoxes, man.
I guess the percent sign not followed by two characters that represent hex for another character?
Tom Ambros
Also, notice on the chart that a group of 57 has a probability of 0.99.
And if you’d rather have the goat?
Relevant XKCD: https://xkcd.com/1282/
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